Transpose of Matrix in C Programming

Transpose of Matrix in C Programming

Hello Programmers! Welcome to Standard Programming. How many of you like doing Matrices in Math? Like it? Then there is a good news for you because today I am gonna show your guys how to find the transpose of a Matrix in C programming.

For those who don't know what Transpose of a Matrix is, if we make the columns of a matrix the row of it and vice versa then the final matrix is called the Transpose of the given Matrix. Lets say a matrix is 

1 2 1 

1 2 3

3 4 5

If we find the Transpose of this Matrix by interchanging the columns and rows it will be

1 1 3

2 2 4

1 3 5

Here we will do the same thing in C Programming with help of For Loops. Here we will run first For Loop to take the elements of the Matrix and second one to change the elements. The code is so simple than any Noob can understand. If you still have any problem understanding the code ask me in the comments, I will surely answer the questions.

#include <stdio.h>
#include <conio.h> 
int main()
{
   int m, n, c, d, matrix[10][10], transpose[10][10];
 
   printf("Enter the number of rows and columns of matrix ");
   scanf("%d%d",&m,&n);
   printf("Enter the elements of matrix \n");
 
   for( c = 0 ; c < m ; c++ )
   {
      for( d = 0 ; d < n ; d++ )
      {
         scanf("%d",&matrix[c][d]);
      }
   }
 
   for( c = 0 ; c < m ; c++ )
   {
      for( d = 0 ; d < n ; d++ )
      {
         transpose[d][c] = matrix[c][d];
      }
   }
 
   printf("Transpose of entered matrix :-\n");
 
   for( c = 0 ; c < n ; c++ )
   {
      for( d = 0 ; d < m ; d++ )
      {
         printf("%d\t",transpose[c][d]);
      }  
      printf("\n");
   }
   getch();
   return 0;
}